Orevița
River in Caraș-Severin County, Romania From Wikipedia, the free encyclopedia
The Orevița is a small left tributary of the river Danube in Romania.[1][2] It discharges into the Danube in Liubcova. Its length is 25 km (16 mi) and its basin size is 102 km2 (39 sq mi).[2]
| Orevița | |
|---|---|
 | |
| Location | |
| Country | Romania |
| Counties | Caraș-Severin County |
| Villages | Valea Orevița |
| Physical characteristics | |
| Mouth | Danube |
• location | Liubcova |
• coordinates | 44.6531°N 21.8870°E / 44.6531; 21.8870][[Category:Pages using gadget WikiMiniAtlas]]"},"html":"Coordinates: </templatestyles>\"}' data-mw='{\"name\":\"templatestyles\",\"attrs\":{\"src\":\"Module:Coordinates/styles.css\"},\"body\":{\"extsrc\":\"\"}}'/>44°39′11″N 21°53′13″E / 44.6531°N 21.8870°E"}"> |
| Length | 25 km (16 mi) |
| Basin size | 102 km2 (39 sq mi) |
| Basin features | |
| Progression | Danube→ Black Sea |
| Tributaries | |
| • right | Orevița Seacă |
References
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