1948 Davis Cup
1948 edition of the Davis Cup From Wikipedia, the free encyclopedia
The 1948 Davis Cup was the 37th edition of the most important tournament between national teams in men's tennis. 25 teams entered the Europe Zone, and four teams entered the America Zone. Pakistan and Turkey made their first appearances in the competition.
| Details | |
|---|---|
| Duration | 22 April – 6 September 1948 |
| Edition | 37th |
| Teams | 29 |
| Champion | |
| Winning nation | United States |
← 1947 1949 → | |
Australia defeated Mexico in the America Zone final, and Czechoslovakia defeated Sweden in the Europe Zone final. Australia defeated Czechoslovakia in the Inter-Zonal play-off, but fell to defending champions the United States in the Challenge Round. The championship was played at the West Side Tennis Club in Forest Hills, New York, United States on 4–6 September.[1][2][3]
America Zone
Draw
Final
Mexico vs. Australia
 Mexico 1 |
Centro Deportivo Chapultepec, Mexico City, Mexico[4] 6–8 August 1948 Clay |
 Australia 4 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Europe Zone
Summarize
Perspective
Draw
Final
Czechoslovakia vs. Sweden
 Czechoslovakia 4 |
Prague, Czechoslovakia[5] 27–29 July 1948 Clay |
 Sweden 1 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Inter-Zonal Final
Australia vs. Czechoslovakia
Australia 3 |
Longwood Cricket Club, Boston, MA, United States[6] 19–22 August 1948 Grass |
Czechoslovakia 2 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Challenge Round
United States vs. Australia
 United States 5 |
West Side Tennis Club, Forest Hills, NY, United States[3] 4–6 September 1948 Grass |
Australia 0 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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References
External links
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