The standard library provides a convenient method of converting numbers into strings, but these strings are
heap-allocated. If you have an application which needs to convert large volumes of numbers into strings, but don't
want to pay the price of heap allocation, this crate provides an efficient no_std-compatible method of heaplessly converting numbers
into their string representations, storing the representation within a reusable byte array.
In addition to supporting the standard base 10 conversion, this implementation allows you to select the base of your choice. Therefore, if you want a binary representation, set the base to 2. If you want hexadecimal, set the base to 16.
This library's API includes const functions that can be used to convert numbers into their string representation at compile time, allowing developers to build smaller & faster executables.
use numtoa::NumToA;
let mut buffer = [0u8; 20];
println!("{}", 12345.numtoa_str(10, &mut buffer));
println!("{}", 256652.numtoa_str(10, &mut buffer));use numtoa::NumToA;
use std::io::{self, Write};
let stdout = io::stdout();
let mut stdout = stdout.lock();
let mut buffer = [0u8; 20];
let number: u32 = 162392;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
assert_eq!(number.numtoa(10, &mut buffer), b"162392");
let number: i32 = -6235;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: i8 = -128;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: i8 = 53;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: i16 = -256;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: i16 = -32768;
let _ = stdout.
71D2
write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: u64 = 35320842;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");
let number: u64 = 18446744073709551615;
let _ = stdout.write(number.numtoa(10, &mut buffer));
let _ = stdout.write(b"\n");