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wgsLR: Shotgun sequencing for human identification: Dynamic SNP marker sets and likelihood ratio calculations accounting for errors

Please refer to the online documentation at https://mikldk.github.io/wgsLR, including the vignettes.

Scientific publication

The research associated with this software is described in

Andersen, M. M., Kampmann, M.-L., Jepsen, A. H., Morling, N., Eriksen, P. S., Børsting, C., & Andersen, J. D. (2025). Shotgun DNA sequencing for human identification: Dynamic SNP selection and likelihood ratio calculations accounting for errors. Forensic Science International: Genetics, 74, 103146. doi:10.1016/j.fsigen.2024.103146.

Installation

To install from Github with vignettes run this command from within R (please install remotes first if not already installed):

# install.packages('remotes')
remotes::install_github("mikldk/wgsLR", build_vignettes = TRUE)

You can also install the package without vignettes if needed as follows:

remotes::install_github("mikldk/wgsLR")

A few small examples

Estimating the genotype error probability, $w$

cases <- wgsLR::sample_data_Hp_w(n = 1000, w = 0.1, p = c(0.25, 0.25, 0.5))
tab <- table(cases$X_D, cases$X_S)
tab
##    
##       0   1   2
##   0 180  55   9
##   1  59 188  88
##   2   4  89 328
w_mle <- wgsLR::estimate_w(tab)
w_mle
## [1] 0.09596158

Cautionary note: not just standard VCF files

It is necessary to obtain sequencing results for all bases in the selected segments (including read depth and genotype quality). Thus, it is not sufficient to just use information from “confirmed”/high probability variants from the reference genome (variants identified in standard vcf-file format), as this can introduce bias in the results. Information from all bases in the chosen genomic areas of interest is needed. One way to achieve this by using GATK HaplotypeCaller with the additional argument --emit-ref-confidence BP_RESOLUTION for the genomic areas of interest (using -L areas.interval_list).

Calculating likelihood ratios ($LR$’s)

Assume that a trace sample had four loci with genotypes (0/1 = 1, 0/0 = 0, 1/1 = 2, 1/1 = 2). A person of interest is then typed for the same four loci and has genotypes (0/0 = 0, 0/0 = 0, 1/1 = 2, 1/1 = 2), i.e. a mismatch on the first locus.

For simplicity, assume that the genotype probabilites are P(0/0 = 0) = 0.25, P(0/1 = 1/0 = 1) = 0.25, and P(1/1 = 2) = 0.5.

If no errors are possible, then $w=0$ and

wgsLR::calc_LRs_w(xs = c(0, 0, 2, 2), 
                  xd = c(1, 0, 2, 2), 
                  w = 0, 
                  p = c(0.25, 0.25, 0.5))
## [1] 0 4 2 2

and the product is 0 due to the mismatch at the first locus.

If instead we acknowledge that errors are possible, then for $w = 0.001$ we obtain that

LR_contribs <- wgsLR::calc_LRs_w(xs = c(0, 0, 2, 2), 
                                 xd = c(1, 0, 2, 2), 
                                 w = 0.001, 
                                 p = c(0.25, 0.25, 0.5))
LR_contribs
## [1] 0.01192834 3.99199202 1.99799850 1.99799850
prod(LR_contribs)
## [1] 0.1900904

We can also consider the $LR$s for a range for plausible values of $w$:

ws <- c(1e-6, 1e-3, 1e-2, 1e-1)
LRs <- sapply(ws, \(w) wgsLR::calc_LRs_w(xs = c(0, 0, 2, 2), 
                                         xd = c(1, 0, 2, 2), 
                                         w = w, 
                                         p = c(0.25, 0.25, 0.5)) |> 
                prod())
data.frame(log10w = log10(ws), w = ws, 
           LR = LRs, WoElog10LR = log10(LRs))
##   log10w     w           LR WoElog10LR
## 1     -6 1e-06 0.0001919981 -3.7167031
## 2     -3 1e-03 0.1900903523 -0.7210399
## 3     -2 1e-02 1.7379421372  0.2400353
## 4     -1 1e-01 7.1409934157  0.8537586

Different error rates

Assume that the trace donor profile has $w_D = 10^{-4}$ and the suspect reference profile has $w_S = 10^{-8}$. Then the $LR$ is:

LR_contribs <- wgsLR::calc_LRs_wDwS(xs = c(0, 0, 2, 2), 
                                    xd = c(1, 0, 2, 2), 
                                    wD = 1e-4, 
                                    wS = 1e-8,
                                    p = c(0.25, 0.25, 0.5))
prod(LR_contribs)
## [1] 0.01279168

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